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Daily · 2026-10-31

Daily math problems for October 31, 2026 — Fundamental Algebra, Descriptive Statistics & Sampling, Euclidean Geometry & more

One bite-sized math problem set for the day. Solve the 10 multiple-choice problems and reveal the worked solutions.

1 / 10
🇬🇧 UK GCSE
Beginnerfundamental-algebra
Make the subject of .

Problems & worked solutions

🇬🇧 UK GCSE

Problem 1 — Rearranging Formulae & Identities

Make xx the subject of y=x+5y=x+5.

Show answer & worked solution
  1. A. x=y−5x=y−5✓ correct
  2. B. x=y+5x=y+5
  3. C. x=5−yx=5−y
  4. D. x=y5x=5y​

y=x+5⇒x=y−5y=x+5⇒x=y−5.

🇺🇸 US SAT

Problem 2 — Notable Values

The exact value of cos⁡ ⁣(π3)cos(3π​) is:

Show answer & worked solution
  1. A. 3223​​
  2. B. 1221​✓ correct
  3. C. 2222​​
  4. D. 11

π3=60∘3π​=60∘, and cos⁡60∘=12cos60∘=21​.

🇬🇧 UK GCSE

Problem 3 — Congruence

Two shapes are congruent if they are:

Show answer & worked solution
  1. A. the same shape and the same sizethe same shape and the same size✓ correct
  2. B. the same shape but any sizethe same shape but any size
  3. C. equal in area onlyequal in area only
  4. D. equal in perimeter onlyequal in perimeter only

Congruent shapes are exactly the same shape and the same size.

🇷🇴 RO M1

Problem 4 — Applications of Derivatives

A particle's position is x(t)=t3−6t2+9tx(t)=t3−6t2+9t (in metres, tt in seconds). The velocity at t=2t=2 is:

Show answer & worked solution
  1. A. −3 m/s−3 m/s✓ correct
  2. B. 0 m/s0 m/s
  3. C. 3 m/s3 m/s
  4. D. 9 m/s9 m/s

v(t)=3t2−12t+9v(t)=3t2−12t+9. At t=2t=2: v=12−24+9=−3v=12−24+9=−3 m/s (the particle is moving backward).

🇷🇴 RO M1

Problem 5 — Groups

In (Z6,+)(Z6​,+), the order of 2^2^ is:

Show answer & worked solution
  1. A. 22
  2. B. 33✓ correct
  3. C. 44
  4. D. 66

2^,4^,6^=0^2^,4^,6^=0^ — three additions, so the order is 33.

🇷🇴 RO M1

Problem 6 — Differentiation

Compute f′(x)f′(x) for f(x)=x2ln⁡xf(x)=x2lnx (with x>0x>0).

Show answer & worked solution
  1. A. 2xln⁡x2xlnx
  2. B. x(2ln⁡x+1)x(2lnx+1)✓ correct
  3. C. x2⋅1xx2⋅x1​
  4. D. 2xln⁡x+x22xlnx+x2

f′(x)=2xln⁡x+x2⋅1x=2xln⁡x+x=x(2ln⁡x+1)f′(x)=2xlnx+x2⋅x1​=2xlnx+x=x(2lnx+1).

🇷🇴 RO M1

Problem 7 — Logic & Induction

Which statement is logically equivalent to "if n2n2 is even, then nn is even"?

Show answer & worked solution
  1. A. If n is even, then n2 is evenIf n is even, then n2 is even
  2. B. If n is odd, then n2 is oddIf n is odd, then n2 is odd✓ correct
  3. C. If n2 is odd, then n is evenIf n2 is odd, then n is even
  4. D. n is even if and only if n2 is oddn is even if and only if n2 is odd

The contrapositive of "n2n2 even ⇒⇒ nn even" is "nn odd ⇒⇒ n2n2 odd". A statement and its contrapositive always have the same truth value.

🇷🇴 RO M1

Problem 8 — Conic Sections

A line is tangent to the circle x2+y2=25x2+y2=25 at (3,4)(3,4). Its equation is:

Show answer & worked solution
  1. A. 3x+4y=53x+4y=5
  2. B. 3x−4y=253x−4y=25
  3. C. 3x+4y=253x+4y=25✓ correct
  4. D. 4x+3y=254x+3y=25

3x+4y=253x+4y=25.

🇷🇴 RO M1

Problem 9 — Rings & Fields

The set of units (multiplicatively invertible elements) of Z8Z8​ is:

Show answer & worked solution
  1. A. {0^}{0^}
  2. B. {1^,2^,3^}{1^,2^,3^}
  3. C. {1^,3^,5^,7^}{1^,3^,5^,7^}✓ correct
  4. D. Z8∖{0^}Z8​∖{0^}

The units are the residues coprime to 88: {1,3,5,7}{1,3,5,7}, four elements.

🇷🇴 RO M1

Problem 10 — Complex Numbers

For n≥2n≥2, the sum of all nnth roots of unity equals:

Show answer & worked solution
  1. A. 00✓ correct
  2. B. 11
  3. C. nn
  4. D. 1nn1​

The polynomial zn−1zn−1 has zero coefficient for zn−1zn−1, so by Viète's formula the sum of its roots is 00. Equivalently, the geometric sum ∑k=0n−1e2πik/n=1−11−e2πi/n=0∑k=0n−1​e2πik/n=1−e2πi/n1−1​=0 (for n≥2n≥2).

Practise these topics

  • Applications of Derivatives
  • Differentiation
  • Conic Sections
  • Complex Numbers
2026-10-30
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