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Solving Triangles practice questions — A-Level Maths

12 free multiple-choice problems on solving triangles, ordered to match A-Level Maths difficulty, each with a full worked solution. No account needed — and there's a fresh problem set every day.

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Problem #0538 International
Mediumtrigonometry
In , , , . The inradius is closest to:

Problems & worked solutions

Problem #0538 International

Problem 1 — Solving Triangles

In △ABC, a=5, b=6, c=7. The inradius r is closest to:

Show answer & worked solution
  1. A. 1.4
  2. B. 1.6✓ correct
  3. C. 2.4
  4. D. 3.0

s=9. By Heron, Area =9⋅4⋅3⋅2=66≈14.70. So r≈14.709≈1.63.

Problem #0938 US SAT

Problem 2 — Solving Triangles

In a triangle, a is opposite ∠A=30∘ and b is opposite ∠B=90∘. If a=5, then b equals:

Show answer & worked solution
  1. A. 5
  2. B. 52
  3. C. 10✓ correct
  4. D. 53

5sin⁡30∘=bsin⁡90∘.

sin⁡30∘=12 and sin⁡90∘=1, so 51/2=b1.

b=10.

Problem #0939 US SAT

Problem 3 — Solving Triangles

In a triangle, two sides have lengths 4 and 5 and the included angle is 60∘. The length of the third side is:

Show answer & worked solution
  1. A. 41
  2. B. 21✓ correct
  3. C. 61
  4. D. 3

c2=42+52−2(4)(5)cos⁡60∘=16+25−40⋅12=41−20=21.

So c=21.

Problem #0536 International

Problem 4 — Solving Triangles

The area of a triangle with sides 5, 6, 7 is closest to:

Show answer & worked solution
  1. A. 10
  2. B. 12
  3. C. 14.7✓ correct
  4. D. 21

s=5+6+72=9. A=9⋅4⋅3⋅2=216=66≈14.70.

Problem #0534 International

Problem 5 — Solving Triangles

In △ABC, ∠A=π6, ∠B=π4, and a=4. The side b equals:

Show answer & worked solution
  1. A. 22
  2. B. 4
  3. C. 42✓ correct
  4. D. 82

4sin⁡(π/6)=bsin⁡(π/4)⇒41/2=b2/2⇒8=b2/2⇒b=8⋅22=42.

Problem #0537 International

Problem 6 — Solving Triangles

In △ABC, a=6 and ∠A=π6. The circumradius R equals:

Show answer & worked solution
  1. A. 3
  2. B. 3
  3. C. 6✓ correct
  4. D. 12

2R=asin⁡A=61/2=12⇒R=6.

Problem #0535 International

Problem 7 — Solving Triangles

In △ABC, AB=5, BC=12, AC=13. The area equals:

Show answer & worked solution
  1. A. 20
  2. B. 24
  3. C. 30✓ correct
  4. D. 60

Since 52+122=132, △ABC is right-angled at B. Area =12⋅5⋅12=30.

Problem #0532 International

Problem 8 — Solving Triangles

In △ABC, AB=6, AC=8, and ∠A=π6. The area equals:

Show answer & worked solution
  1. A. 48
  2. B. 24
  3. C. 12✓ correct
  4. D. 6

Area =12⋅6⋅8⋅sin⁡π6=24⋅12=12.

Problem #0531 International

Problem 9 — Solving Triangles

A right triangle has legs 3 and 4. Its area equals:

Show answer & worked solution
  1. A. 5
  2. B. 6✓ correct
  3. C. 7
  4. D. 12

Area =12⋅3⋅4=6.

Problem #0533 International

Problem 10 — Solving Triangles

In △ABC, a=7, b=8, c=5. The value of cos⁡C is:

Show answer & worked solution
  1. A. 114
  2. B. 1116
  3. C. 1114✓ correct
  4. D. 58

25=49+64−112cos⁡C⇒112cos⁡C=88⇒cos⁡C=88112=1114.

2 more Solving Triangles questions in the app

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