Daily · 2026-08-04
One bite-sized math problem set for the day. Solve the ten multiple-choice problems and reveal the worked solutions.
The limit equals:
grows without bound: .
On , define . Then
The sum of all real solutions of is:
The limit
Find
The value of
The value of is:
At a meeting, every pair of people shakes hands exactly once. If there are handshakes total, how many people are there?
On Monday at 7:00 a.m. a monk begins climbing a winding mountain trail, arriving at the summit at 5:00 p.m. The next morning at 7:00 a.m. she begins descending the same trail and reaches the base at 5:00 p.m. There must exist a point on the trail and a clock time at which the monk was at the same place on both days. Which classical theorem most directly justifies this?
Let be the trail length. Define
- : the monk's distance from the base on Monday at time
For , the entry
.
gives or . Sum .
Compute the modulus of the base:
.
, and , so .
.
Both functions are continuous on (a hiker doesn't teleport).
Now consider . By the problem statement:
- and , so . - and , so .
Since is continuous and changes sign on , the Intermediate Value Theorem guarantees some with , i.e. . At that clock time, the monk stands at the same point on the trail on both days.
The physical intuition ("imagine two monks: one ascending Monday, one descending Tuesday at the same time — they must meet") collapses into a one-line IVT argument once you let do the work.
By induction, , so .
Modulus distributes over powers:
The denominator is real and positive, so: