Daily · 2026-07-12
One bite-sized math problem set for the day. Solve the ten multiple-choice problems and reveal the worked solutions.
The limit equals:
The remainder of
The general solution of is:
Compute .
For
Let
The polynomial has exactly:
Among rectangles with perimeter , the one with maximum area has dimensions:
Show by induction that
The value of
.
.
.
. Evaluating from to : .
Build the pieces for
everywhere, so is strictly increasing on . Combined with , has exactly one real root by IVT.
. . The maximum-area rectangle is the square , with area .
. (Direct: .)
The fifth roots of unity sum to . Subtracting the root leaves a sum of , and taking real parts gives
Assemble and take the determinant:
For we have and:
Assemble :
Multiply the two determinants: