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Daily · 2026-05-05

Daily math problems for May 5, 2026 — Combinatorics, Compound Interest, Exponential Functions

One bite-sized math problem set for the day. Solve the 3 multiple-choice problems and reveal the worked solutions.

1 / 3
🌍 International
MediumCombinatorics
An airplane row has 3 seats: window, middle, aisle. You're seating 3 people: Alice prefers the window, Bob prefers the aisle, Carol has no preference. In how many of the possible orderings is everyone happy (i.e., neither Alice nor Bob ends up away from their preferred seat)?

Problems & worked solutions

🌍 International

Problem 1 — Combinatorics

An airplane row has 3 seats: window, middle, aisle. You're seating 3 people: Alice prefers the window, Bob prefers the aisle, Carol has no preference. In how many of the 3!=63!=6 possible orderings is everyone happy (i.e., neither Alice nor Bob ends up away from their preferred seat)?

Show answer & worked solution
  1. A. 11✓ correct
  2. B. 22
  3. C. 33
  4. D. 66

Alice must take the window seat (1 way). Bob must take the aisle seat (1 way). Carol takes the middle (1 way). Only 1×1×1=11×1×1=1 ordering satisfies both preferences.

More generally — when each person's preference is for a distinct seat, only the permutation that matches preferences exactly is 'fully happy'.

🌍 International

Problem 2 — Compound Interest

How long, in years, does it take for an investment to double at 7% annual interest, compounded annually? (Use the closest answer.)

Show answer & worked solution
  1. A. About 7 yearsAbout 7 years
  2. B. About 10 yearsAbout 10 years✓ correct
  3. C. About 14 yearsAbout 14 years
  4. D. About 70 yearsAbout 70 years

We need tt such that (1.07)t=2(1.07)t=2, i.e. t=ln⁡2ln⁡1.07≈0.6930.0677≈10.24t=ln1.07ln2​≈0.06770.693​≈10.24 years.

The banker's shortcut: the Rule of 72 — divide 72 by the interest rate. 72/7≈10.372/7≈10.3. Quick, accurate enough.

🌍 International

Problem 3 — Exponential Functions

Solve for xx: 2x+1=3x2x+1=3x.

Show answer & worked solution
  1. A. x=log⁡32x=log3​2
  2. B. x=ln⁡2ln⁡3−ln⁡2x=ln3−ln2ln2​✓ correct
  3. C. x=log⁡23x=log2​3
  4. D. x=ln⁡2ln⁡3x=ln3ln2​

Take ln⁡ln of both sides: (x+1)ln⁡2=xln⁡3(x+1)ln2=xln3.

Expand: xln⁡2+ln⁡2=xln⁡3xln2+ln2=xln3.

Collect xx: ln⁡2=x(ln⁡3−ln⁡2)ln2=x(ln3−ln2).

So x=ln⁡2ln⁡3−ln⁡2≈0.6930.405≈1.71x=ln3−ln2ln2​≈0.4050.693​≈1.71.

2026-05-04
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